bash - grep and process substitution -

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• why should there space after '[' , before ']' in bash? 4 answers

i'm trying use process substitution grep follows:

#!/bin/bash if [grep -c "*" <(cut -d"," -f5 input_q1.csv) ]   echo "yes"; else   echo "no"; fi 

but i'm getting error:

line 2: [grep: command not found 

what missing?

[ ... ] not part of syntax of if-statement; rather, [ (also called test) bash built-in command commonly used test-command in if-statement.

in case, test-command grep rather [, write:

if grep -c "*" <(cut -d"," -f5 input_q1.csv) ; 

additionally, there's no real reason use process substitution here. overall result of pipeline result of final command in pipeline; , grep supports reading standard input. can write:

if cut -d"," -f5 input_q1.csv | grep -c "*" ; 

to support wider range of systems.

(incidentally, quotation marks around , don't anything: -d"," means -d, means "-d,". if goal "highlight" delimiter, or set off in way, might make more sense split separate argument: -d ,. that's matter of preference.)