PHP wrapping a code inside a function makes that code not workable -

i have code , works perfectly:

if(in_array($_server['http_host'], array('localhost', '127.0.0.1'))) // localhost {     $root = ''; } else {     if(!empty($_server['https'])) // https     {         $root = 'https'.'://'.$_server['https_host'];     }     else // http     {         $root = 'http'.'://'.$_server['http_host'];     } } 

i echo way:

<img src="<?php echo $root.htmlspecialchars($path, ent_quotes); ?>" /> 

i want wrap code inside function like:

function root() { // code } 

and echo similar way this:

<img src="<?php echo root().htmlspecialchars($path, ent_quotes); ?>" /> 

how it? because example doesn't work. :(

your function doesn't return value, there's nothing echoing... try adding return $root @ end of function:

function root() {     //that code     return $root; }