python - How to round decimal digits always up -

this question has answer here:

• how round off floating number? 9 answers

so ran trouble rounding floats up, code:

foo = float(0.21) bar = float(0.871929)  foobar = foo * bar rfoobar = round(foobar,2) 

this gives me:

foobar = 0.1831 rfoobar = 0.18 

but want rfoobar 0.19, how accomplish rounds digits when there remainder?

i read math.ceiling in case doesn't seem trick.

any appreciated.

just move decimal point before , after calling ceil:

from math import ceil  rfoobar = ceil(foobar * 100) / 100 

if number of decimals varies, can like:

rfoobar = ceil(foobar * 10 ** digits) / 10 ** digits