ruby - Looking at a hash as an array? -

i found example of using #any? on hash bit tricky:

"with hash, can use these in 2 ways. either 1 argument 2 element array of key-value pair. candidate[0] key , candidate[1] value.

{:locke => 4, :hugo => 8}.any? { |candidate| candidate[1] > 4 }  

this returns true because value of second candidate :hugo greater 4."

could point me someplace explains happened here? couldn't find relevant question on so. lot in advance.

if print candidate become easy understand:

{:locke => 4, :hugo => 8}.any? { |candidate| puts candidate.to_s }  # [:locke, 4] # [:hugo, 8] 

the any? method treating each key-value pair of hash two-element array, means hash treated array of arrays.

the block passed any? (i.e., { |candidate| candidate[1] > 4 }) returns true if of the second elements (i.e., 4 , 8) ever > 4 , false otherwise. 8 > 4, result true.

from official docs, any? method:

passes each element of collection given block. method returns true if block ever returns value other false or nil. if block not given, ruby adds implicit block of { |obj| obj } cause any? return true if @ least 1 of collection members not false or nil.