c - Command line arguments, printing columns and rows -

i'm trying print out characters given input command-line arguments. i'm having bit of trouble wrapping head around this.

when run ./test foo bar want print

./test foo o o  bar r 

while might not best solution, want done using arrays of arrays of chars, , looks three-dimensional array, i'm going triple-nested for-loop. have far this:

for (i = 1; < argc; i++) {     (j = 0; j < argv[argc][j]; j++) {         (k = 0; k < argv[argc][j]; k++) {             printf("%c", k);         }     }     printf("\n"); } 

the outermost loop starts @ 1, since don't want print out ./test-bit. i'm lost. can work two-dimensional arrays, wanted try out dimension.

can give me few pointers?

your condition(j < argv[argc][j], k < argv[argc][j]) wrong.

fix this:

#include <stdio.h>  int main(int argc, char *argv[]){     (int = 0; < argc; i++) {         puts(argv[i]);         if(i){             for(int j = 1; argv[i][j]; ++j){                 printf("%c\n", argv[i][j]);             }             printf("\n");         }     }     return 0; }