c++ - How can I continue the process and print out their process ids? -

#include <sys/types.h> #include <stdio.h> #include <unistd.h> #include <sys/wait.h> using namespace std;  int main () {  int pid;  printf ("\ni'm original process pid %d.\n", getpid ());  pid = fork ();                     /* duplicate process. child , parent continue here */  if (pid != 0)                      /* pid non-zero, must parent */    {      printf ("i'm parent process pid %d.\n", getpid());      printf ("my child's pid %d.\n", pid);    }  else                              /* pid zero, must child */    {      printf ("i'm child process pid %d.\n", getpid ());      pid= fork();            printf ("i'm child's child pid %d.\n", getpid ());        }  printf ("pid %d terminates.\n", getpid()); } 

so far program working, need program continue 9 more processes indicating process 2 parent of process 3 , process 3 parent of process 4, , on. far i've been able output parent process id, along child process id. issue is, outputs parent , child once. require program create chain of 10 processes , prints out parent , child process id's. i've been able output parent id , child id once. best method accomplish this?

you can try out this:

#include <stdio.h> #include <unistd.h> #include <sys/types.h> #include <sys/wait.h>  static int counter = 1;      void init_proc() {     pid_t pid;     pid = fork();     if(pid==0)     {         if(counter==10)         {             return;         }         else         {             counter++;             init_proc();         }     }     else if(pid > 0)     {         int status;         waitpid(pid, &status, wnohang);         printf("process %d child %d\n", getpid(), pid);     }     else     {         fprintf(stderr,"error: not initialize process\n");     } }      int main () {      init_proc();      return 0; } 

notice pid != 0 doesn't mean in parrent process. if fork() returns -1 means there error. more info here: http://linux.die.net/man/2/fork .

in example didn't use printf's wanted can play little results want.