linux - using alarm(3) with out exit from program-- c++ -

here code.

 #include<iostream> int main() {     std::string str;     while(true)     {     std::cout<<"enter string \n";     alarm(3);     getline(std::cin,str);        // calling function in other class,            , return here (if not entered string in 3 sec)      }     return 0; } 

after 2 sec exiting program. but, want continue calling function , return same getline(). possible?? thanks

if read reference page of alarm see that:

the alarm() function shall cause system generate sigalrm signal process after number of realtime seconds specified seconds have elapsed.

you need catch sigalrm signal, example using sigaction system call.